The dating math problem

And now we can tackle the real question: Why do math writers have an obsession with trains? Check out this “Wheel of Fortune” puzzle that had everyone scratching their heads not too long ago.

Welcome to our reviews of the carbon dating math problem (also known as extremely beautiful women).

If Alice accepted his proposal, yet is not married to him at the end, she must have dumped him for someone she likes more, and therefore doesn't like Bob more than her current partner.

If Alice rejected his proposal, she was already with someone she liked more than Bob.

At the end, there cannot be a man and a woman both unengaged, as he must have proposed to her at some point (since a man will eventually propose to everyone, if necessary) and, being proposed to, she would necessarily be engaged (to someone) thereafter.

Let Alice and Bob both be engaged, but not to each other.

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Except that while the internet has a lot of answers, a lot of those answers are wrong.

After all, 5×3 is 15 last time we GIPHYRELATED: Can You Find The Horse Hidden In This Frog Picture?

Regardless, all of the people who posted about the answer being 46 have since deleted their posts in embarrassment, so I think we can put this controversy to rest.

All three are stable, because instability requires one of the participants to be happier with an alternative match.

Giving one group their first choices ensures that the matches are stable because they would be unhappy with any other proposed match.

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